8r^2+14r-9=10r

Solution for 8r^2+14r-9=10r equation:

8r^2+14r-9=10r

We move all terms to the left:

8r^2+14r-9-(10r)=0

We add all the numbers together, and all the variables

8r^2+4r-9=0

a = 8; b = 4; c = -9;
Δ = b2-4ac
Δ = 42-4·8·(-9)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{19}}{2*8}=\frac{-4-4\sqrt{19}}{16}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{19}}{2*8}=\frac{-4+4\sqrt{19}}{16}
$